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60x^2-68x+8=0
a = 60; b = -68; c = +8;
Δ = b2-4ac
Δ = -682-4·60·8
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-52}{2*60}=\frac{16}{120} =2/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+52}{2*60}=\frac{120}{120} =1 $
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